Java >>> Operator [duplicate]

Answer 1

From Java tutorial:

The unsigned right shift operator ">>>" shifts a zero into the leftmost position, while the leftmost position after ">>" depends on sign extension.

Answer 2

You can see the difference with a simple program:

public static void main(String[] args) throws InterruptedException, IOException {
    int i = -1;
    int j = i >> 1;
    int k = i >>> 1;
    System.out.println("i = " + i + "\t\t<=> " + Integer.toBinaryString(i));
    System.out.println("j = " + j + "\t\t<=> " + Integer.toBinaryString(j));
    System.out.println("k = " + k + "\t<=> " + Integer.toBinaryString(k));
}

output:

i = -1          <=> 11111111111111111111111111111111  
j = -1          <=> 11111111111111111111111111111111  
k = 2147483647  <=> 1111111111111111111111111111111

Answer 3

the signed right shift operator ">>" shifts a bit pattern to the right.The unsigned right shift operator ">>>" shifts a zero into the leftmost position,

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