Sizeof array through function in C [duplicate]

Answer 1

Because arrays are passed as reference. Meaning only pointer to array is passed. Sizeof inside the function would only print the size of pointer, not the size of array.

Besides just making sure you know, size of returns number of bytes, so if you have an integer array (where int is of size 4 for e.g. sizeof would give elements * 4 as output.

Answer 2

int searchMe(int numbers[], int target)

is equivalent to

int searchMe(int *numbers, int target)

There is a special C rules for function parameters that says parameters of array type are adjusted to a pointer type.

It means in your program that sizeof numbers actually yields the size of the int * pointer type and not of the array.

To get the size you have to add a third parameter to your function and explicitly pass the size of the array when you call the function.