Why aren't newlines being printed in this Perl code?

Question

I have some simple Perl code:

#!/usr/bin/perl

use strict;   # not in the OP, recommended
use warnings; # not in the OP, recommended

my $val = 1;
for ( 1 ..         


        

Answer 1

It is possible that the line is interpreted as follows

(print($val / 8050)) . " \n";

i.e. the parentheses being used as delimiters for a function argument list, with the ."\n" being silently discarded. Try:

 print( ($val/8050) . "\n" );

Answer 2

This is more of a comment than an answer, but I don't know how else to make it and the question is already answered anyway.

Note that using say instead of print neatly sidesteps the whole issue. That is,

#!/usr/bin/perl

use 5.010;
use strict;
use warnings;

my $val = 1;
for ( 1 .. 100 ) {
    $val = ($val * $val + 1) % 8051;
    say ($val / 8050);
}

works as intended without the issue even coming up. I'm still amazed at how useful say is, given it's such a tiny difference.

Answer 3

C:\> perldoc -f print:

Also be careful not to follow the print keyword with a left parenthesis unless you want the corresponding right parenthesis to terminate the arguments to the print--interpose a + or put parentheses around all the arguments.

Therefore, what you need is:

print( ($val / 8050) . "\n" );

or

print +($val / 8050) . "\n";

The statement you have prints the result of $val / 8050 and then concatenates "\n" to the return value of print and then discards the resulting value.

Incidentally, if you:

use warnings;

then perl will tell you:

   print (...) interpreted as function at t.pl line 5.
   Useless use of concatenation (.) or string in void context at t.pl line 5.