getting segmentation fault in a small c program

Question

i wrote a small prog :

  1 #include  
  2 main(){  
  3         char* str = \"string\";  
  4         *str = \'k\';  
  5         printf(\"str         


        

Answer 1

char* str = "string";

This puts the string in read-only memory. It is undefined behavior (usually unpleasant behavior) when you try to modify it with the next line. Try something like

char str[] = "string";

instead.

Answer 2

I also executed the given code..

  1 #include<stdio.h>  
  2 main(){  
  3         char* str = "string";  
  4         *str = 'k';  
  5         printf("string is = %s\n",str);
  6 }

 But there is no such error. 

 Following output is shown....

 String is=Ktring

 A segmentation fault, bus error, or access violation is generally an attempt 
 to access memory that the CPU cannot physically address. So in my opinion it's   
 completely depends on execution.

 thanks...

Answer 3

char * str = "string";

declares a pointer which points to an area of memory where the string "string" is stored; it's undefined behavior to write in this area of memory, and it usually results in a crash.

Instead, you should use:

char str[]="string";

which declares a string local to your function, that is initialized to the value "string". Since the memory you are using for this string is local to your procedure you can alter it however you want.