mysqli query only returning first row

Question

I am migrating from mysql to mysqli, and I am having trouble returning more than one row from the database in a query.

$db = new mysqli($hostname, $sql_us, $         


        

Answer 1

You need to store while loop values into array try this

$rows = array();
if ($type == 'assoc') {
    while($row = $result->fetch_assoc()) {
      $rows[] = $row;
    }
} else {    
    while($row = $result->fetch_object()) {
      $rows[] = $row;
    }   
}
return $rows;

Answer 2

$arr = array();
if ($type == 'assoc') {
  while($row = $result->fetch_assoc()) {
    $arr[] = $row;
  }
}
else {    
  while($row = $result->fetch_object()) {
    $arr[] = $row;   
  }
}
return $arr;

Answer 3

You are only returning the first row. You have to return an array.

Answer 4

When you return in a function it stops executing at that point and goes back to the where it was called from with the value that you are returning.

In your case when you do a return $row, you are getting out of the function as soon as the first row is read.

Fix is:

$result = array();
if ($type == 'assoc') {
    while($row = $result->fetch_assoc()) {
      $result[] = $row;
    }

} else {    

    while($row = $result->fetch_object()) {
      $result[] = $row;
    }   
}
return $row;

Answer 5

Use this code:

$rows = array();
if ($type == 'assoc') {
    while($row = $result->fetch_assoc()) {
      $rows[] = $row;
    }
} else {    
    while($row = $result->fetch_object()) {
      $rows[] = $row;
    }   
}
return $rows;

You are using the return inside the while and return terminates the while loop after first iteration that's why you are getting only one row.