Filter a column which contains several keywords

Question

I am trying to filter a column which contains several keywords (in this example dog and cat) but I am having problems as only the first element is being used.

Answer 1

Here is a dplyr method:

library(stringi)
library(dplyr)

data = data_frame(
  id = c(1:7),
  type = c("dog1","dog2" ,"cat1","cat2","zebra1", "parrot5", "elephant15")
)


data %>%
  filter(animals %>%
           paste(collapse = "|") %>%
           stri_detect_regex(type, . ) )

Answer 2

Like @Tgsmith61591 mentioned, the pattern argument for the grep function requires a string. Since you're passing in a vector it's warning you that it will only process the first element.

Another solution would be something like this:

dfilter <- unique(grep(paste(filter1, collapse = "|"), df1$type, value=TRUE))

See this post grep using a character vector with multiple patterns

Answer 3

Try this:

dfilter <- df1[sapply(filter1, function(x) grep(x,df1$type)),]

It's complaining because your filter is a vector and grep wants a string.

Edit:

From this answer:

dfilter <- df1[df1$type %in% grep(paste(filter1, collapse="|"), df1$type, value=TRUE), ]

Answer 4

df1[(gsub('\\d','',df1$type) %in% filter1),]
  id type
1  1 dog1
2  2 dog2
3  3 cat1
4  4 cat2

Answer 5

grep can use | as an or, so why not paste your filters together with | as a separator:

dfilter <- df1[grep(paste0(filter1, collapse = "|"), df1$type),]