I\'ve got a pretty good understanding of python\'s try-except clause, but I\'m encountering problems when trying to put it inside of a function.
>>>
The name error is happening before it ever gets into tryAppend. It evaluates the value of foo when trying to pass it to the function. This works:
def tryAppend(child, parent):
parent.append(child)
var1 = []
try:
tryAppend(foo, var1)
except NameError:
print 'WRONG NAME'
foo
exception happens even before you enter the function tryAppend()
i.e. outside of the function.
For someone who is looking for how to use try except construction inside of the function. I am not sure whether it is a good programming style, but it works.
You can put string arguments to the function. It will be evaluated correctly and then you can use exec
inside of the function:
def tryAppend(child, parent):
try:
script = parent + '.append(' + child + ')'
exec script
return parent
except NameError:
print "WRONG NAME"
var1 = []
var2 = 'test2'
tryAppend('var2', 'var1')
tryAppend('foo', 'var1')
The NameError is being thrown when the name 'foo' is evaluated, which is before entering the function. Therefore the try/except within the function isn't relevant.
tryAppend(foo, var1)
is evaluated (roughly) in this order:
tryAppend
referencesfoo
referencesvar1
referencestryAppend
does, uncluding the try-except)The error occurs at #2, long before the function and the try block is entered. In fact, the try block cannot to throw a NameError, as the only names used are parent
and child
, both being arguments and thus always available (if .append
does not exist, that's an AttributeError
).
In the same way, the following code will not print "caught it" because the exception is raised before the try block is executed:
raise Exception("Catch me if you can")
try:
pass # do nothing
except:
print "caught it"
This has nothing to do with your exception handler. The error you are seeing is because "foo" is not defined anywhere.