how to solve f(n) = f((3/4)n) + f(n^(1-b)) + c n^b

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旧时难觅i
旧时难觅i 2020-12-11 21:03

How can I solve this recurrence :

f(n) = f((3/4)n) + f(n^(1-b)) + c n^b

where b and c are constants and 0

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