I have many data.frames, for example:
df1 = data.frame(names=c(\'a\',\'b\',\'c\',\'c\',\'d\'),data1=c(1,2,3,4,5))
df2 = data.frame(names=c(\'a\',\'e\',\'e\',
First define a function, run.seq
, which provides sequence numbers for duplicates since it appears from the output that what is desired is that the ith duplicate of each name in each component of the merge be associated. Then create a list of the data frames and add a run.seq
column to each component. Finally use Reduce
to merge them all.
run.seq <- function(x) as.numeric(ave(paste(x), x, FUN = seq_along))
L <- list(df1, df2, df3)
L2 <- lapply(L, function(x) cbind(x, run.seq = run.seq(x$names)))
out <- Reduce(function(...) merge(..., all = TRUE), L2)[-2]
The last line gives:
> out
names data1 data2 data3
1 a 1 1 NA
2 b 2 NA NA
3 c 3 4 1
4 c 4 5 NA
5 d 5 6 NA
6 e NA 2 2
7 e NA 3 NA
EDIT: Revised run.seq
so that input need not be sorted.
I think there is just not enough information in your example data frames to do this. Which 'c'
in dataframe 1 should be paired with which 'c'
in data frame 2? We cannot tell, so R can't either. I suspect you will have to add another variable to each of your dataframes that uniquely identifies these duplicate cases.
See other questions:
Examples:
library(reshape)
out <- merge_recurse(L)
or
library(plyr)
out<-join(df1, df2, type="full")
out<-join(out, df3, type="full")
*can be looped
or
library(plyr)
out<-ldply(L)