Extract Scheme and Host from HTTP_REFERER

Question

I have $_SERVER[\'HTTP_REFERER\'] — pretend it is http://example.com/i/like/turtles.html. What would I need to do to get just the http://example.com

Answer 1

You should be able to use the parse_url function to achieve that

Answer 2

You could use a regular expression:

if (isset($_SERVER['HTTP_REFERER']) && preg_match('@^[^/]+://[^/]+@', $_SERVER['HTTP_REFERER'], $match)) {
    var_dump($match[0]);
}

Or you could use the parse_url function.

Answer 3

I'd use parse_url in the following way...

if ($urlParts = parse_url($myURI))
  $baseUrl = $urlParts["scheme"] . "://" . $urlParts["host"];

Answer 4

In this example, the best solution would be to use PHP's parse_url method. This splits up the URL into an associative array. You would then build your final value by combining the scheme with the host:

if ( $parts = parse_url( "http://example.com/i/like/turtles.html" ) ) {
    echo $parts[ "scheme" ] . "://" . $parts[ "host" ];
}