Swift error: 'missing return in function'?

Question

I am creating a tic tac toe game and I came upon this error that I don\'t really understand: \"Missing return in a function expected to return \'(location:String, pattern:St

Answer 1

Since your return type is an optional, you could do this:

func rowcheck(value:Int)->(location:String, pattern:String)? {
  var goodFinds = ["011","101","110"]
  var findFuncs = [checktop, checkbottom, checkmidAcross, checkleft, checkmidDown, checkright, checkLRdiag, checkRLdiag]
  for algor in findFuncs {
    var algorResults = algor(value)
    if find(goodFinds,algorResults.pattern) {
        return algorResults
    }
  }
   return nil
}

Answer 2

func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
    let button = DropDownButton()
    switch button {
    case userButton:
        return userButton.dropView.dropDownOptions.count
    case categoryButton:
        return categoryButton.dropView.dropDownOptions.count
    default:
        return 0
    }

Answer 3

You could use a switch statement. Here is an example I have used:

  func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
    let button = DropDownButton()
    switch button {
    case userButton:
        return userButton.dropView.dropDownOptions.count
    case categoryButton:
        return categoryButton.dropView.dropDownOptions.count
    default:
        return 0
    }

Thought it might help somebody, Happy coding

Answer 4

Your code only returns a value if find(goodFinds,algorResults.pattern) is satisfied, but there is no return value otherwise.

What you can do is to specify a default return value and do something like this (pseudo-code only):

variable result = defaultvalue

if find(goodFinds,algorResults.pattern) {
        result = algorResults
    }

return result

I should mention that I am not familiar with Swift, but this logic would ensure that you always return something, so that your method fulfills the contract.