HTML/PHP - default input value

Question

I have a post php form and a set of inputs:

1. Your Name
2. Your Last Name
3. My Name

Every input looks the same, only the names change

Answer 1

You need to check the return of get_option first, and substitute something if a default is not available

<?php
    $default = get_option('your_name');
    if( $default == "")
    {
        $default = <whatever your default value is>;
    }
?>
<input type="text" name="your_name" value="<?php echo $default; ?>" />

Change get_option to return an empty string (or something else) if the default is not available.

Answer 2

Simply use a ternary operator. its pretty easy try this

$default = 'Mike';

$your_name = get_option('your_name');

$condition = !empty($your_name) ? $your_name : $default;

<input type="text" name="your_name" value="<?php echo $condition; ?>" />

Answer 3

This is How I solved this issue in my problem which I believe is similar, when $_POST is read the value is populated from the $_POST value else sets a default of Mike

value="<?php if (isset($_POST['name'])) echo $_POST['name']; else echo "Mike"?>" >

Hope this helps someone oneday

Answer 4

<input type="text" name="your_name" value="<?php echo empty(get_option('your_name')) ? "TheDefaultValue" : get_option('your_name'); ?>" />

Answer 5

I agree with Teneff but I would break it out.

In the index.php I would have the following at the top of the doc

<?
$defaultText = include 'default_text.php';  
?>

where your forms are it would be:

<form method="post" action="">
<input id="names"><? echo $defaultText; ?> </input> 
</form> 

then I would have a seperate file on the root level called "default_text.php."

<?
$Name = <<<EOD Name EOD;
return $Name;
?>

Answer 6

You can do a switch statement and have default to be whatever you want it to be.