In TypeScript, what exactly is type \'{}\'
and how does it relate to other built-in types?
For example, the last line of the following example gives
You need to have your call function like this:
function call<T>(fn: NoArgsFn<T>): T {
return fn();
}
In your original call
function you had 2 generic types which you did not pass when calling the function and the compiler failed to infer what types they are.
Type {}
is an object literal (as far as I'm aware), and so you can face the same error like this:
var o = {};
var n: number = o; // Error: Type '{}' is not assignable to type 'number'
I'm not exactly sure why the compiler inferred that the function returns {}
in your example.
type {}
Consider the object type { id: number, name: string }
, which represents a 2-field object. Legal values of this type include { id: 1, name: "Foo" }
and { id: 2, name: "Bar" }
.
The type object {}
represents a 0-field object. The only legal value of this type is an empty object: {}
.
So the value { id: 1, name: "Foo" }
is of type { id: number, name: string }
, and the value {}
(i.e. an empty object) is of type {}
.
The error seems to be a bug in the TypeScript compiler (I submitted an issue here). It fails to infer the type arguments in the call to call
. You can work around this by explicitly specifying the type arguments:
let the_answer: number = call<number, NoArgsFn<number>>(get_the_answer);
But it's simpler and more straightforward to use a single type argument instead, as @NitzanTomer suggested:
function call<T>(fn: NoArgsFn<T>): T {
return fn();
}
EDIT: I issue I submitted was closed as a duplicate of #7234 which is to be fixed before the release of TypeScript 2.0.
As far as I know, {}
casts directly to a hash map like usage. You can only use keyed properties, versus the dot notation.
var o:{} = {}
should be equivalent to
var o:{[key:string]:any} = {}
So
o.x = 5; //fails
But
o['x'] = 5; //succeeds