Scala Tuple Deconstruction

Question

I am new to Scala, and ran across a small hiccup that has been annoying me.

Initializing two vars in parallel works great: var (x,y) = (1,2)

How

Answer 1

Unfortunately, you cannot do multiple assignments in Scala. But you may use tuples, if they fit your problem:

scala> var xy = (1,2)
xy: (Int, Int) = (1,2)

scala> xy = (xy._1 + xy._2, xy._2 - xy._1)
xy: (Int, Int) = (3,1)

This way, xy is one tuple with two values. The first value can be accessed using xy._1, the second one using xy._2.

Answer 2

Scala has 2 types of variables: vals and vars. Vals are similar to Java's final variables, so as far as I understand from what you're asking, the only way to assign new values in parallel to vals is by:

scala> val (x, y) = (1, 2);

or

scala> val s = (3, 4);
s: (Int, Int) = (3,4)

scala> s._1
res1: Int = 3

scala> s._2
res2: Int = 4