I\'m trying to get the highest and lowest numbers entered by the user. The code below seems to be mostly working but I can\'t seem to get the right number for the lowest val
import java.io.*;
public class jem3
{
public static void main(String []args)
{
BufferedReader dataIn = new BufferedReader(new InputStreamReader( System.in ));
int high;
int lowest;
int num;
System.out.println("Enter number");
num=Integer.parseInt(dataIn.readLine());
lowest = highest = num;
for(int a=0;a<10;a++)
{
try
{
num=Integer.parseInt(dataIn.readLine());
}
catch(IOException e)
{
System.out.println("error");
}
if(num>high)
{
high=num;
}
if(num<lowest)
{
lowest=num;
}
}
System.out.println("highest is:"+ high);
System.out.println("lowest is: "+lowest);
}
}
i added code after reeading first line to set high and lowest, so if user will give you 10 numbers '9' it will output lowest number being '9' and not 1 as it would (similiar with high).
you are on the right track for capturing highest
. you need to apply similar logic for lowest
.
What is the purpose of A
? You're not modifying lowest
either. You're close, try this:
num = ...
if ( num > max ) max = num;
if ( num < min ) min = num;
System.out.println("Highest: " + max);
System.out.println("Lowest: " + min);
import java.io.*;
public class jem3{
public static void main(String []args){
BufferedReader dataIn = new BufferedReader(new InputStreamReader(System.in));
int high=0;
int lowest=0;
int num=0;
boolean test = true;
System.out.println("Enter number");
for(int a=0;a<10;a++)
{
try
{
num=Integer.parseInt(dataIn.readLine());
}
catch(IOException e)
{
System.out.println("error");
}
if(num>high)
{
high=num;
}
//add an initial value to 'lowest'
if (test)
lowest = num;
test = false;
if(num < lowest)
{
lowest = num;
}
}
System.out.println("highest is:"+ high);
System.out.println("lowest is: "+ lowest);
}
}