Xslt : Create a namespace dynamically

Question

Following are the nodes in XML Data

\"http://webser.part.site\"
nida


        

Answer 1

I. This XSLT 2.0 transformation:

<xsl:stylesheet version="2.0"   xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
    <xsl:output omit-xml-declaration="yes" indent="yes"/>
    <xsl:param name="pUrl" select="'some: namespace'"/>

 <xsl:template match="/*">
     <xsl:element name="{name()}"
          namespace="http://schemas.xmlsoap.org/soap/envelope/">
      <xsl:sequence select="namespace::*[not(name()='web')]"/>
      <xsl:namespace name="web" select="$pUrl"/>
     </xsl:element>
 </xsl:template>
</xsl:stylesheet>

when applied on the provided XML document:

<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/"
                  xmlns:web="http://webser.part.site"/>

produces the wanted, correct result (the 'web' namespace produced from the value of a parameter):

<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/"
                  xmlns:web="some: namespace"/>

---

II. This XSLT 1.0 transformation:

<xsl:stylesheet version="1.0"   xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
 xmlns:ext="http://exslt.org/common" exclude-result-prefixes="ext">
    <xsl:output omit-xml-declaration="yes" indent="yes"/>
    <xsl:param name="pUrl" select="'some: namespace'"/>

    <xsl:variable name="vrtfDummy">
     <xsl:element name="web:dummy" namespace="{$pUrl}"/>
    </xsl:variable>

    <xsl:variable name="vNS" select="ext:node-set($vrtfDummy)/*/namespace::web"/>

 <xsl:template match="/*">
     <xsl:element name="{name()}"
          namespace="http://schemas.xmlsoap.org/soap/envelope/">
      <xsl:copy-of select="namespace::*[not(name()='web')]"/>
      <xsl:copy-of select="$vNS"/>
     </xsl:element>
 </xsl:template>
</xsl:stylesheet>

when applied on the same XML document (above), again produces the wanted, correct result:

<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:web="some: namespace"/>