Ensuring that my program is not doing a concurrent file write

Question

I am writing a script that is required to perform safe-writes to any given file i.e. append a file if no other process is known to be writing into it. My understanding of th

Answer 1

Use the lockfile module as shown in Locking a file in Python

Answer 2

Inspired from a solution described for concurrency checks, I came up with the following snippet of code. It works if one is able to appropriately predict the frequency at which the file in question is written. The solution is through the use of file-modification times.

import os
import time

'''Find if a file was modified in the last x seconds given by writeFrequency.'''
def isFileBeingWrittenInto(filename, 
                       writeFrequency = 180, overheadTimePercentage = 20):

    overhead = 1+float(overheadTimePercentage)/100 # Add some buffer time
    maxWriteFrequency = writeFrequency * overhead
    modifiedTimeStart = os.stat(filename).st_mtime # Time file last modified
    time.sleep(writeFrequency)                     # wait writeFrequency # of secs
    modifiedTimeEnd = os.stat(filename).st_mtime   # File modification time again
    if 0 < (modifiedTimeEnd - modifiedTimeStart) <= maxWriteFrequency:
        return True
    else:
        return False

if not isFileBeingWrittenInto('fileForSafeWrites.txt'):
    handle = open('fileForSafeWrites.txt', 'a')
    handle.write("Text written safely when no one else is writing to the file")
    handle.close()

This does not do true concurrency checks but can be combined with a variety of other methods for practical purposes to safely write into a file without having to worry about garbled text. Hope it helps the next person searching for a way to do this.

EDIT UPDATE:

Upon further testing, I encountered a high-frequency write process that required the conditional logic to be modified from

if 0 < (modifiedTimeEnd - modifiedTimeStart) < maxWriteFrequency 

to

if 0 < (modifiedTimeEnd - modifiedTimeStart) <= maxWriteFrequency 

That makes a better answer, in theory and in practice.