How do I distribute values of an array in three columns?

Question

I need this output..

1 3 5
2 4 6

I want to use array function like array(1,2,3,4,5,6). If I edit this array like array(1

Answer 1

Here's something I whipped up. I'm pretty sure this could be more easily accomplished if you were using HTML lists, I've assumed you can't use them.

$arr    = array(1,2,3,4,5,6,7,8,9,10,11,12,13,14, 15, 16);
$max    = count($arr);
$cols   = 3;
$block  = ceil($max / $cols);
for ($i = 0; $i < $block ; $i++) {
    echo $arr[$i] . ' ';

    for ($j = 1; $j < $cols; $j++) {
        $nexKey = $i  + $block * $j;
        if (!isset($arr[$nexKey])) break;   
        echo $arr[$nexKey] . ' ';
    }
    echo '<br>';
}

NOTE : You can easily refactor the code inside the loop that uses $nexkey variable by making it into a loop itself so that it works for any number of columns. I've hardcoded it.

Uses loops now.

Answer 2

One solution is to cut the array into chunks, representing the columns, and then print the values in row order:

$cols = array_chunk($arr, ceil(count($arr)/3));
for ($i=0, $n=count($cols[0]); $i<$n; $i++) {
    echo $cols[0][$i];
    if (isset($cols[1][$i])) echo $cols[1][$i];
    if (isset($cols[2][$i])) echo $cols[2][$i];
}

If you don’t want to split your array, you can also do it directly:

for ($c=0, $n=count($arr), $m=ceil($n/3); $c<$m; $c++) {
    echo $arr[$c];
    for ($r=$m; $r<$n; $r+=$m) {
        echo $arr[$c+$r];
    }
}

Answer 3

You can do a loop that will automatically insert a new line on each three elements:

$values = array(1,1,1,1,1);

foreach($values as $i => $value) {
  printf('%-4d', $value);

  if($i % 3 === 2) echo "\n";
}

EDIT: Since you added more information, here's what you want:

$values = array(1,2,3,4,5);

for($line = 0; $line < 2; $line++) {
  if($line !== 0) echo "\n";

  for($i = $line; $i < count($values); $i+=2) {
    printf('%-4d', $values[$i]);
  }
}

And if you want to bundle all that in a function:

function print_values_table($array, $lines = 3, $format = "%-4d") {
  $values = array_values($array);
  $count = count($values);

  for($line = 0; $line < $lines; $line++) {
    if($line !== 0) echo "\n";

    for($i = $line; $i < $count; $i += $lines) {
      printf($format, $values[$i]);
    }
  }
}

EDIT 2: Here is a modified version which will limit the numbers of columns to 3.

function print_values_table($array, $maxCols = 3, $format = "%-4d") {
  $values = array_values($array);
  $count = count($values);
  $lines = ceil($count / $maxCols);

  for($line = 0; $line < $lines; $line++) {
    if($line !== 0) echo "\n";

    for($i = $line; $i < $count; $i += $lines) {
      printf($format, $values[$i]);
    }
  }
}

So, the following:

$values = range(1,25);
print_array_table($values);

Will output this:

1   10  19  
2   11  20  
3   12  21  
4   13  22  
5   14  23  
6   15  24  
7   16  25  
8   17  
9   18  

Answer 4

one solution is : your array has N elements, and you want 3 columns, so you can get the value of each cell with $myarray[ column_index + (N/3) + line_index ] (with one or two loops for columns and lines, at least for lines) I hope this will help you Bye

Answer 5

$a = array(1,2,3,4,5);
"{$a[0]} {$a[1]} {$a[2]}\n{$a[3]} {$a[4]}";

or

$a = array(1,2,3,4,5);
"{$a[0]} {$a[1]} {$a[2]}".PHP_EOL."{$a[3]} {$a[4]}";

or

$a = array(1,2,3,4,5);
$second_row_start = 3; // change to vary length of rows
foreach( $a as $index => $value) {
  if($index == $second_row_start) echo PHP_EOL;
  echo "$value ";
}

or, perhaps if you want a longer array split into columns of 3?

$a = array(1,2,3,4,5,6,7,8,9,10,11,12,13);
$row_length = 3; // change to vary length of rows
foreach( $a as $index => $value) {
  if($index%$row_length == 0) echo PHP_EOL;
  echo "$value ";
} 

which gives

1 2 3 
4 5 6 
7 8 9 
10 11 12 
13