Bulk renaming of files based on lookup

Question

I have a folder full of image files such as

• 1500000704_full.jpg
• 1500000705_full.jpg
• 1500000711_full.jpg
• 1500000712_full.jpg

Answer 1

Here's a fun little hack:

paste -d " " lookupfile.txt lookupfile.txt | cut -d " " -f 2,3 | sed "s/\([ ]\|$\)/_full.jpg /g;s/^/mv /" | sh

Answer 2

Here's a simple Python 2 script to do the rename.

#!/usr/bin/env python

import os

# A dict with keys being the old filenames and values being the new filenames
mapping = {}

# Read through the mapping file line-by-line and populate 'mapping'
with open('mapping.txt') as mapping_file:
    for line in mapping_file:
        # Split the line along whitespace
        # Note: this fails if your filenames have whitespace
        new_name, old_name = line.split()
        mapping[old_name] = new_name

suffix = '_full'

# List the files in the current directory
for filename in os.listdir('.'):
    root, extension = os.path.splitext(filename)
    if not root.endswith(suffix):
        # File doesn't end with this suffix; ignore it
        continue
    # Strip off the number of characters that make up suffix
    stripped_root = root[:-len(suffix)]
    if stripped_root in mapping:
        os.rename(filename, ''.join(mapping[stripped_root] + suffix + extension))

Various bits of the script are hard-coded that really shouldn't be. These include the name of the mapping file (mapping.txt) and the filename suffix (_full). These could presumably be passed in as arguments and interpreted using sys.argv.

Answer 3

#!/bin/bash

for FILE in *.jpg; do
    OLD=${FILE%.*}  # Strip off extension.
    NEW=$(awk -v "OLD=$OLD" '$2==OLD {print $1}' map.txt)
    mv "$OLD.jpg" "$NEW.jpg"
done

Answer 4

Read in the text file, create a hash with the current file name, so files['1500000704'] = 'SH103239' and so on. Then go through the files in the current directory, grab the new filename from the hash, and rename it.

Answer 5

import os,re,sys

mapping = <Insert your mapping here> #Dictionary Key value entries (Lookup)

for k,v in mapping:
    for f in os.listdir("."):
        if re.match('1500',f): #Executes code on specific files
            os.rename(f,f.replace(k,v))

Answer 6

This will work for your problem:

#!/usr/bin/perl
while (<DATA>) {
    my($new, $old) = split;
    rename("$old.jpg", "$new.jpg")
        || die "can't rename "$old.jpg", "$new.jpg": $!";
}
__END__
SH103239 1500000704
SH103240 1500000705
SH103241 1500000711
SH103242 1500000712
SH103243 1500000714
SH103244 1500000744
SH103245 1500000745
SH103252 1500000802
SH103253 1500000803
SH103254 1500000804

Switch to ARGV from DATA to read the lines from a particular input file.

Normally for mass rename operations, I use something more like this:

#!/usr/bin/perl
# rename script by Larry Wall
#
# eg:
#      rename 's/\.orig$//'  *.orig
#      rename 'y/A-Z/a-z/ unless /^Make/'  *
#      rename '$_ .= ".bad"'  *.f
#      rename 'print "$_: "; s/foo/bar/ if <STDIN> =~ /^y/i'  *
#      find /tmp -name '*~' -print | rename 's/^(.+)~$/.#$1/'

($op = shift) || die "Usage: rename expr [files]\n";

chomp(@ARGV = <STDIN>) unless @ARGV;

for (@ARGV) {
    $was = $_;
    eval $op;
    die if $@;  # means eval `failed'
    rename($was,$_) unless $was eq $_;
}

I’ve a more full-featured version, but that should suffice.