How to copy a certain number of chars from a file to a vector the STL-way?

Question

If I want to copy the contents of a file to a vector, I can do it like that:

std::ifstream file(\"path_to_file\");
std::vector buffer(std::istrea         


        

Answer 1

char *buffer = new char[n];
file.read(buffer,n);
std::vector<char> myVector
for (int i=0;i<n;i++) myVector.push_back(buffer[i]);
delete [] buffer;

// myVector now holds the first n bytes of file.

It may not be the prettiest or quickest way, but it is how I would do it.

Answer 2

Credit due to @sbi, I forgot about generate_n.

The streambuf inside file has a function snextc which returns the next character, qualifying it as a generator function, once its implicit this argument is bound.

generate_n( back_inserter( buffer ), 42,
            tr1::bind( tr1::mem_fn( &streambuf::snextc ), file.rdbuf() ) );

For vector, just read directly. This is good for deque or whatever.

Answer 3

As Alexander points out, the fastest way would be

std::vector<char> buffer(n);
file.read(&buffer[0], n);

In C++0x, you can use buffer.data() instead of &buffer[0]; the latter has undefined behavior if n == 0.

Answer 4

As was noted by Steve, this would need copy_n(), which, due to an oversight, isn't in the current standard library, but will be in C++1x. You can implement one yourself easily, here's one I believe to be correct:

template<class InIt, class OutIt> 
OutIt copy_n(InIt src, OutIt dest, size_t n) 
{
  if (!n) return dest;
  *dest = *src;
  while (--n)
    *++dest = *++src;
  return ++dest; 
} 

Note that std::copy_n() presumes the input iterator to be able to deliver n objects. When reading from a file, this could be problematic.

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Absent of std::copy_n(), you could use std::generate_n.

template< typename InIt >
struct input_generator {
  typedef std::iterator_traits<InIt>::value_type value_type;

  input_generator(InIt begin, InIt end) begin_(begin), end_(end) {}

  value_type operator()()
  {
    assert(it_ != end);
    return *it_++;
  }

  Init begin_;
  Init end_;
};


std::vector<char> buffer;
buffer.reserve(42);

std::generate_n( std::back_inserter(buffer)
               , 42
               , input_generator(std::istream_iterator<char>(file))
               , input_generator(std::istream_iterator<char>()) );

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However, I don't see this as an advantage over reading directly from the file as avakar showed.

Answer 5

The "STL way" is to use copy_n, which is in the STL but not the C++ standard.