Evaluating strlen at compilation time?

Question

If my code has this constexpr string

constexpr char my_str[] = \"hello\";

the type of my_str contains information

Answer 1

21.8, 1 and 2, in the standard says:

1. Tables 74, 75, 76, 77, 78, and 79 describe headers <cctype>, <cwctype>, <cstring>, <cwchar>, <cstdlib> (character conversions), and <cuchar>, respectively.

2. The contents of these headers shall be the same as the Standard C Library headers <ctype.h>, <wctype.h>, <string.h>, <wchar.h>, and <stdlib.h> and the C Unicode TR header <uchar.h>, respectively, with the following modifications:

strlen is defined in in <cstring> in c++. The modifications that follow do not mention strlen. From that, I would conclude that the signature in C++ must be exactly the same as it is in C, and since C does not have constexpr, it is technically non-compliant. That said, this is one of those non-compliant things that's unlikely to do any harm, beyond relying on it on one platform and then not finding it on another.

Answer 2

Firstly, you might be confusing the functionality of the two: strlen() gives the length of the whole string and sizeof() gives the size of memory space occupied by the data type in memory.

The function sizeof() is a compile-time expression because the memory to your variable is allocated during compile-time(given its not dynamically written). Thus, giving you the size of memory occupied by the data type. It doesn't care about the value of the variable, just cares about memory space.

Whereas, strlen() is a function that takes a pointer to a character, and keeps incrementing the memory from this character o, looking for a NULL character, which is at the end of the string. It counts the number of characters before it finds the NULL character.Basically, giving you the length.

Answer 3

In C++17 you can use std::char_traits::length, which is constexpr, instead of strlen.