Rounding off a positive number to the next nearest multiple of 5

Question

I need to round of a number (the input is guaranteed to be an integer & is positive) to the next multiple of 5.

I tried this:

int round = ((grade         


        

Answer 1

You can take the difference between grades[j] and the next number, and just add it. For example, if grades[j] == 12 then 12 mod 5 == 2, so add 5 - 2.

Here is a sample program to test it out:

#include <iostream>

int main() {
    int x[] = {2,7,123,32}; // some random numbers to show how this works
    for (int i = 0; i < 4; {
        std::cout << x[i] << "\t" << x[i] + ((5-(x[i] % 5)) % 5) << std::endl;
    }
    return 0;
}

Output:

2   5
7   10
123 125
32  35