Serialization of a lambda after its creation

Question

I can serialize a lambda with the following syntax:

Runnable r = (Runnable & Serializable) () -> System.out.println(\"\");
try (ObjectOutput oo = new          


        

Answer 1

This is correct, and by design. Just as you cannot take a non-serializable object and make it serializable after instantiation, once a lambda is created, its serializability is set.

A lambda is serializable if its target type is serializable (and its captured arguments are serializable.) Your first example is serializable because the target type is the intersection (Runnable & Serializable). Your two attempts to convert r fail because in both cases, r is a captured variable that is not serializable, and so the resulting lambda expression / method reference is not serializable. (The receiver for a bound method reference acts as a captured variable.)