the reason: python string assignments accidentally change '\b' into '\x08' and '\a' into '\x07', why Python did this?

Question

Had two answers and some comments, mentioned another question, but all had not provided REASON, why Python did this changes? such as \'/b\' is \'/x08\' is just the result, b

Answer 1

Escape sequence \a, \b is equivalnt to \x07, \x08.

>>> '\a'
'\x07'
>>> '\b'
'\x08'

You should escape \ itself to represent backslash literally:

>>> '\\a'
'\\a'
>>> '\\b'
'\\b'

or use raw string literals:

>>> r'\a'
'\\a'
>>> r'\b'
'\\b'

Answer 2

Your strings are being escaped. Check out the docs on string literals:

The backslash () character is used to escape characters that otherwise have a special meaning, such as newline, backslash itself, or the quote character. String literals may optionally be prefixed with a letter r' orR'; such strings are called raw strings and use different rules for backslash escape sequences.

This is a historical usage dating from the early 60s. It allows you to enter characters that you're not otherwise able to enter from a standard keyboard. For example, if you type into the Python interpreter:

print "\xDC"

...you'll get Ü. In your case, you have \b - representing backspace - which Python displays in the \xhh form, where hh is the hexadecimal value for 08. \a is the escape sequence for the ASCII bell: try print "\a" with your sound on and you should hear a beep.