C# simple divide problem

Question

I have this:

 double result = 60 / 23;

In my program, the result is 2, but correct is 2,608695652173913. Where is problem?

Answer 1

60 and 23 are integer literals so you are doing integer division and then assigning to a double. The result of the integer division is 2.

Try

double result = 60.0 / 23.0;

Or equivalently

double result = 60d / 23d;

Where the d suffix informs the complier that you meant to write a double literal.

Answer 2

Haven't used C# for a while, but you are dividing two integers, which as far as I remember makes the result an integer as well.

You can force your number literals to be doubles by adding the letter "d", likes this:

double result = 60d / 23d;

Answer 3

double result = 60.0 / 23.0;

Answer 4

It is best practice to correctly decorate numerals for their appropriate type. This avoids not only the bug you are experiencing, but makes the code more readable and maintainable.

double x = 100d;
single x = 100f;
decimal x = 100m;

Answer 5

convert the dividend and divisor into double values, so that result is double
double res= 60d/23d;

Answer 6

(double) 60 / 23