How Do I Use VBScript to Strip the First n Characters of a String?

Question

How do I use VBScript to strip the first four characters of a string?

Ss that the first four characters are no longer part of the string.

Answer 1

You have several options, some of which have already been mentioned by others:

• Use a regular expression replacement:

  s = "abcdefghijk"
  n = 4
  
  Set re = New RegExp
  re.Pattern = "^.{" & n & "}"  'match n characters from beginning of string
  
  result = re.Replace(s, "")
  

• Use the Mid function:

  s = "abcdefghijk"
  n = 4
  result = Mid(s, n+1)
  

• Use the Right and Len functions:

  s = "abcdefghijk"
  n = 4
  result = Right(s, Len(s) - n)
  

Usually string operations (Mid, Right) are faster, whereas regular expression operations are more versatile.

Answer 2

You can use

MyString = Mid(First_String, 5)

Answer 3

Try this (just create sample.vbs with this content):

Option Explicit

Dim sText

sText = "aaaaString"
sText = Right(sText, Len(sText) - 4)

MsgBox(sText)

Answer 4

I request you to use the following script to strip first 4 characters of your string StringName = Mid(StringName,5)