SQL - order by list order

Question

I have the following query that returns rows based on a comma seperated list

Select * from Table where RecordID in (22,15,105,1,65,32)

I wo

Answer 1

Use ORDER BY against the RecordID

Select * from Table where RecordID in (22,15,105,1,65,32) ORDER BY RecordID 

Answer 2

If you need the output to appear in a particular order, then you need to specify that order, using something the server can sort. Not knowing which engine you're working against, the general scheme would be to create a temp table or use rowset constructors to pair each record ID with its desired sort order.

E.g. (SQL Server)

declare @T table (RecordID int,Position int)
insert into @T (RecordID,Position)
select 22,1 union all
select 15,2 union all
select 105,3 union all
select 1,4 union all
select 65,5 union all
select 32,6

select * from Table t inner join @T t2 on t.RecordID = t2.RecordID order by t2.Position

Answer 3

Yes. You add the ORDER BY recordedid clause at the end.

Answer 4

select * from Table
where RecordID in (22,15,105,1,65,32)
order by (
    case RecordID 
        when 22 then 1
        when 15 then 2
        when 105 then 3
        when 1 then 4
        when 65 then 5
        when 32 then 6 end)

Answer 5

The last time I had to do this I ended up doing a union all and generating a select statement for each id, i.e.

select * from Table where RecordID = 22
union all
select * from table where recordid = 15

etc.

It was a pain but it worked.

Answer 6

I'd to the ordering in the client, but if you really want to do it in SQL, do it like this:

declare @T table (id int identity(1,1), RecordID int)

insert into @T (RecordID)
values (22), (15), (105), (1), (65), (32)

select * from 
[table] t 
inner join @t s on t.id=s.recordid
where t.id in (22, 15, 105, 1, 65, 32)
order by s.id

(works in SQL Server 2008)