This is purely an Excel sheet question.
I have a time span that is basically a difference between two cells, each containing a date:
I have managed to get th
The following is certainly not the shortest formula and not a direct answer to the question but works to show the correct result (also on LibreOffice) in the following format:
# days ## hours ## minutes ## seconds
=CONCATENATE(TEXT(FLOOR(B2-A2,1),"@")," days ", IF(HOUR(A12)-HOUR(A11)<0,HOUR(A12)-HOUR(A11)+24,HOUR(A12)-HOUR(A11))," hours ",IF(MINUTE(A12)-MINUTE(A11)<0,MINUTE(A12)-MINUTE(A11)+60,MINUTE(A12)-MINUTE(A11)), " minutes ", TEXT(B2-A2,"s"), " seconds")
=IFERROR(INT(Date1-Date2)&" Days "&INT(MOD((Date1-Date2);INT(Datw1-Date2))*24)&" Hours "&MINUTE(Fate1-Date)&" Min";IFERROR((Date1-Date2);"NA"))enter code here
I think this should do the trick, whatever date you have.
Warning: the above only works for ranges less than 31 days. use
=CONCATENATE(TEXT(FLOOR(B1-A1,1),"@")," Days",TEXT(B1-A1," h:mm:ss"))
instead for ranges above 31 days. This will not sort well, so it would be better to do the calculation in one column and then prettify that column for the end result.
You can use TEXT
=TEXT(B1-A1,"d:h:mm")
Note the same effect can be achieved using a simple number format on the cells directly
C1, C2
etc)d:hh:mm
If unlike your example data, your date differences exceed 31 days, then an approach such as
=INT(B1-A1)&":"&TEXT(B1-A1,"h:mm")
will work
Had a similar kind of question, except for me, I needed hours divided by 8, instead of 24, as I needed working days. So I came up with a solution, but it's really really complex to understand because the code looks like a mess, but if you segment them, it's not that hard.
=CONCAT(INT(C16*24/8),":",IF(INT((C16-INT(C16))*24)<10,CONCAT("0",INT((C16-INT(C16))*24)),INT((C16-INT(C16))*24)),":",IF(MINUTE(C16)<10,CONCAT("0",MINUTE(C16)),MINUTE(C16)))
Unfortunately it appears number and datetime formats cannot be combined, otherwise a custom format of:
0:h:m
would be the ticket. However, if for spans of 32 days or more, you are satisfied with just displaying the number of (fractional) days you can use a custom format like:
[>=32] 0.00 "days"; d:h:m
The cell value remains numeric.