Compare 2 files and remove any lines in file2 when they match values found in file1

Question

I have two files. i am trying to remove any lines in file2 when they match values found in file1. One file has a listing like so:

File1

ZNI008
ZNI009         


        

Answer 1

I like the grep solution from byrondrossos better, but here's another option:

sed $(awk '{printf("-e /%s/d ", $1)}' file1) file2 > file3

Answer 2

What about:

grep -F -v -f file1 file2 > file3

Answer 3

this is using Bash and GNU sed because of the -i switch

cp file2 file3
while read -r; do
    sed -i "/$REPLY/d" file3
done < file1

---

there is surely a better way but here's a hack around -i :D

cp file2 file3
while read -r; do
    (rm file3; sed "/$REPLY/d" > file3) < file3
done < file1

this exploits shell evaluation order

---

alright, I guess the correct way with this idea is using ed. This should be POSIX too.

cp file2 file3
while read -r line; do
    ed file3 <<EOF
/$line/d
wq
EOF
done < file1

---

in any case, grep seems to do be the right tool for the job.
@byrondrossos answer should work for you well ;)

Answer 4

This is admittedly ugly but it does work. However, the path must be the same for all of the (except of course the ZNI### portion). All but the ZNI### of the path is removed so the command grep -vf can run correctly on the sorted files.

First Convert "testfile2" to "testfileconverted" to just show the ZNI###

cat /testfile2 | sed 's:^.*_ZNI:ZNI:g' | sed 's:_.*::g' > /testfileconverted

Second use inverse grep of the converted file compared to the "testfile1" and add the reformatted output to "testfile3"

bash -c 'grep -vf <(sort /testfileconverted) <(sort /testfile1)' | sed "s:^:\copy /Y \\\|server\\\foldername\\\version\\\20050001_:g" | sed "s:$:_162635\.xml \\\|server\\\foldername\\\version\\\folder\\\:g" | sed "s:|:\\\:g" > /testfile3