Replace images source for all images

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不思量自难忘°
不思量自难忘° 2020-12-10 21:14

I want to replace the src attribute for all images matching a regex using Greasemonkey scripting. Example:

Replace http://aff.kooora.com/i/z3.gif

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  • 2020-12-10 21:39

    Your regular expression is the problem, you need to wrap it in slashes (otherwise the interpreter has no clue that it should treat that as a regexp):

    var allImg=document.getElementsByTagName("img"), i=0, img;
    
    var pattern = /^http\:\/\/aff\.kooora\.com\/(.*)$/;
    
    while (img = allImg[i++])
    {
        if (img.src.match(pattern)) {
            img.src = img.src.replace(pattern, 'http://example.com/aff.kooora.com/$1');
        }
    }
    
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  • 2020-12-10 21:42

    Just an alternative.

    In this Greasemonkey script, ProxyLoadIMG, this is accomplished without using regex.

    It was created to load images through a proxy.
    Only the images. Links and other content remains untouched.

    var proxy = 'https://proxytea.appspot.com/'
    
    for (var x=0; x<document.images.length; x++) {
        imagem = document.images[x];
        imagem.src = imagem.src.replace(location.protocol + '//', proxy);
    }
    

    http://aff.kooora.com/i/any.jpg becomes https://proxytea.appspot.com/aff.kooora.com/i/any.jpg
    http://aff.kooora.com/i/z3.gif becomes https://proxytea.appspot.com/aff.kooora.com/i/z3.gif
    and so on...

    No RegEx needed :)

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  • 2020-12-10 21:54

    Use this:

    function replaceImages(oldUrl, newUrl) {
        var imgs = document.getElementsByTagName('img')
        for (i = 0; i<imgs.length; i++) {
            imgs[i].src = imgs[i].src.replace(oldUrl, remoteUrl)
        }
    }
    
    replaceImages('http://aff.kooora.com/i/z3.gif', 'http://example.com/aff.kooora.com/i/z3.gif')
    

    This is also great if you're working on a local version of a site and you can't be bothered to download all their image content

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