Sum of strings extracted from text file using regex

Question

I am just learning python and need some help for my class assignment.

I have a file with text and numbers in it. Some lines have from one to three numbers and other

Answer 1

import re
text = open('text_numbers.txt')
data=text.read()
print sum(map(int,re.findall(r"\b\d+\b",data)))

Use .read to get content in string format

Answer 2

import re

fl=open('regex_sum_7469.txt')
ls=[]

for x in fl: #create a list in the list
   x=x.rstrip()
   print x
   t= re.findall('[0-9]+',x) #all numbers
   for d in t: #for loop as there a empthy values in the list a
        ls.append(int(d))
print (sum(ls))

Answer 3

Here is my solution to this problem.

import re

file = open('text_numbers.txt')
sum = 0 

for line in file:
    line = line.rstrip()
    line = re.findall('([0-9]+)', line)
    for i in line:
        i = int(i)
        sum += i    

print(sum)

The line elements in first for loop are the lists also and I used second for loop to convert its elements to integer from string so I can sum them.

Answer 4

import re
sample = open ('text_numbers.txt')
total =0
dignum = 0 

for line in sample:
    line = line.rstrip()
    dig= re.findall('[0-9]+', line)

    if len(dig) >0:
        dignum += len(dig)
        linetotal= sum(map(int, dig))
        total += linetotal

print 'The number of digits are:  ' 
print dignum
print 'The sum is: '
print total     
print 'The sum ends with: '
print  total % 1000

Answer 5

I dont know much python but I can give a simple solution. Try this

import re
hand = open('text_numbers.txt')
x=list()
for line in hand:
    y=re.findall('[0-9]+',line)
    x=x+y
sum=0
for i in x:
    sum=sum + int(i)
print sum

Answer 6

import re
import np
text = open('text_numbers.txt')
final = []
for line in text:
    line = line.strip()
    y = re.findall('([0-9]+)',line)

    if len(y) > 0:
         lineVal = sum(map(int, y))
         final.append(lineVal)
         print "line sum = {0}".format(lineVal)
 print "Final sum = {0}".format(np.sum(final))

Is that what you're looking for?