How to send SOAP request and Parse SOAP response in XML format in Android?

Question

Am very new to Android apps development. In my new Android app i want to show some data from webservice. This means i have a SOAP message, i need to parse the d

Answer 1

Google for Ksoap2 tutorial u will get a lot of them . Here is sample code for sending request to web service .

public class WebServicePoc extends Activity{
private static final String SOAP_ACTION = "http://tempuri.org/Arnoid";
private static final String METHOD_NAME = "Arnoid";
private static final String NAMESPACE = "http://tempuri.org/";
private static final String URL = "http://ipaddress:port/UserAuthenticationInterfacer.asmx";
EditText editText;
@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);
    HashMap<String, String> a=new HashMap<String, String>();
    try {

        SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);
        request.addProperty("FOSID", "1994");
        request.addProperty("IMEINumber", "");
        request.addProperty("SIMCardNo", "");
        request.addProperty("ApplicationName", "App");
        request.addProperty("CurrentVersion", "1.0.0.0");
        SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
        envelope.dotNet=true;
        envelope.setOutputSoapObject(request);
        AndroidHttpTransport androidHttpTransport = new AndroidHttpTransport(URL);
        androidHttpTransport.call(SOAP_ACTION, envelope);
        SoapObject result = (SoapObject)envelope.getResponse();
        editText=(EditText)findViewById(R.id.text1);
        editText.setText(result.toString());
    } catch (Exception e) {
        e.printStackTrace();
    }

And for xml pls check tutorial for xml parsers,use SAX only, as STAX is not supported in android . For sending xml request u can send xml as string and then decode on sever side .