XML::LibXML, namespaces and findvalue

Question

I\'m using XML::LibXML to parse an XML document with a namespace. I therefore use XML::LibXML::XPathContext to findnodes using the XPath //u:model

Answer 1

You can't use $node->findvalue() because of the whole default namespace thing. However, you can reuse your XML::LibXML::XPathContext object to find the values you want:

for my $node ( $context->findnodes('//u:model') ) {
   my $mh   = $context->findvalue('u:mh', $node);
   my $attr = $context->findvalue('u:attribute', $node);
   print "mh = $mh, attr = $attr\n";
}

Answer 2

XPath allows ignoring namespaces by using the function local-name:

use XML::LibXML;

my $dom = XML::LibXML->load_xml( IO => \*DATA );

for my $node ( $dom->findnodes('//*[local-name()="model"]') ) {
    my $mh   = $node->findvalue('*[local-name()="mh"]');
    my $attr = $node->findvalue('*[local-name()="attribute"]');

    print "mh = $mh, attr = $attr\n";
}

This removes the need to specify an context for a single namespace document like in the question.

Reference: Re^2: XML::LibXML and namespaces