Type casting and Comparison with Loose Operator “==”

Question

I have a problem baffling me terribly. I noticed this before but didn\'t give it any heed until today. I was trying to write my own check for integer strings. I know of

Answer 1

It's not a bug, it's a feature. Any string can be casted to an integer, but the cast will return 0 if the string doesn't start with an integer value. Also, when comparing an integer and a string, the string is casted to an integer and then the check is done against the two integers. Because of that rule, about just any random string is "equal" to zero. (To bypass this behavior, you should use strcmp, as it performs an explicit string comparison by casting anything passed to a string.)

To make sure I'm dealing with an integer, I would use is_numeric first, then convert the string to an int, and verify that the stringified int corresponds to the input value.

if (is_numeric($value) && strcmp((int)$value, $value) == 0)
{
    // $value is an integer value represented as a string
}

Answer 2

According to php.net http://php.net/manual/en/language.operators.comparison.php:

var_dump(0 == "a"); // 0 == 0 -> true

So, I think it is juggling the types, and actually casting both sides to int. Then comparing either the sum of the ascii values or the ascii values of each respective index in the string.

Answer 3

If you want to compare types of variables too you should use ===.

Answer 4

You made an error with your post, the correct output is this:

bool(true)
bool(true)
int(0)
string(6) "string"

What happens is this:

1. Because you cast the variable to an integer, and you compare it to an integer with a loose comparison ==, PHP will first implicitely cast the string to an integer, a more explicit but 100% equivalent form would be: if((int)$var1 == (int) $var1)
2. See 1), the same thing applies here
3. It prints int(0), as it should, because it fails to parse the number, it will return 0 instead.
4. Prints string(6) "string" - as expected

Answer 5

Here's a function that more rigorously tests for either an int or an integer string.

function isIntegerNumeric($val) {
  return (
    is_int($val)
      || (
        !is_float($val)
          && is_numeric($val)
          && strpos($val, ".") === false
      )
  );
}

It's relatively quick and avoids doing any string checking if it doesn't have to.

Answer 6

First of all in mathematices '=' is called transitive b/c (A=B and B=C => A=C) is valid.

This is not the case with PHPs "=="!

(int)$var1 == $var1

In that case PHP will cast 'string' to 0 - that's a convention.

Then ==-operator will implicitely have the second operand 'string' also be casted to integer -> as well 0.

That leads to true.