I have an xml code :
gordon
100
You can achieve desired result by using XMLTable()
function:
select q.Lastname
, q.Numberid
, s.codeid
, w.LoginId
, q.address
from t1 t
left join xmltable('/begin/entry'
passing t.xml_col
columns LastName varchar2(21) path 'lastname',
NumberId number path 'NumberList/number',
Address varchar2(201) path 'address/addresslist',
CodeList XmlType Path 'NumberList/codelist/code',
Logins XmlType Path 'NumberList/login/user'
) q
on (1=1)
left join xmltable('/code'
passing q.CodeList
columns CodeId number path '.') s
on (1=1)
left join xmltable('/user'
passing q.Logins
columns LoginId varchar2(11) path '.') w
on (1=1)
Result: SQLFiddle Demo
Lastname Numberid Codeid Loginid Address
---------------------------------------------------------------------------
gordon 100 213 user1 Jl. jalan pelan-pelan ke Bekasi, Indonesia
gordon 100 213 user2 Jl. jalan pelan-pelan ke Bekasi, Indonesia
gordon 100 214 user1 Jl. jalan pelan-pelan ke Bekasi, Indonesia
gordon 100 214 user2 Jl. jalan pelan-pelan ke Bekasi, Indonesia
mark null null null Jl. jalan cepet-cepet ke Jakarta, Indonesia
Find out more about XMLTable()
function.
Note: Working with Oracle releases prior to 11.2.0.2, you can encounter ORA-1780 error
(bug 8545377) on certain types of XML queries when cursor_sharing
parameter is set to FORCE
or SIMILAR
(deprecated starting from 11.2). Setting cursor_sharing
parameter to EXACT
(default value), will solve the problem.