java.text.ParseException: Unparseable date: “Thu Jan 19 2012 08:00 PM”

Question

I would like to parse a date. My String date is \"Thu Jan 19 2012 08:00 PM\". And my code to parse is:

format = new SimpleDateFormat(\"EEE MMM dd yyyy hh:mm          


        

Answer 1

// make sure your string date and DateFormat pattern are same; // for example you have String date="2018/07/10 10:00:00";

                            DateFormat format = new SimpleDateFormat( "yyyy/MM/dd HH:mm:ss");

                            // now makesure format has same pattern in this case ""yyyy/MM/dd HH:mm:ss"

Answer 2

Try below code... Tested and worked

    String dateStr = "Thu Jan 19 2012 01:00 PM";
    DateFormat readFormat = new SimpleDateFormat( "EEE MMM dd yyyy hh:mm aaa");

    DateFormat writeFormat = new SimpleDateFormat( "yyyy-MM-dd HH:mm:ss");
    Date date = null;
    try {
       date = readFormat.parse( dateStr );
    } catch ( ParseException e ) {
        e.printStackTrace();
    }

    String formattedDate = "";
    if( date != null ) {
    formattedDate = writeFormat.format( date );
    }

    System.out.println(formattedDate);

Output is 2012-01-19 13:00:00

Cheers!!! Happy to help!!!

Answer 3

What is your default locale? Since the date string is in English, try parsing it with the US locale:

DateFormat format = new SimpleDateFormat("EEE MMM dd yyyy hh:mm a", Locale.US);

Answer 4

Try setting a Locale such as US in this case:

SimpleDateFormat format = new SimpleDateFormat("EEE MMM dd yyyy hh:mm aaa",Locale.US);
format.parse("Thu Jan 19 2012 08:00 PM");

Answer 5

Make sure that value really got to that call. Put a breakpoint right on that line and double check actual value.

As you can see here http://ideone.com/MBzYn code works perfectly.