C++: dynamically allocating a member array of structs using non-default constructor

Question

If I have:

struct a_struct
{
    int an_int;

    a_struct(int f) : an_int(f) {}
    a_struct() : an_int(0) {}
};

class a_class
{
    a_struct * my_structs;         


        

Answer 1

If using the STL is an option, you could use std::vector instead of a dynamic array.

I think that this will work:

std::vector<a_struct> my_structs;

my_structs.assign(10, 1);

If not, this should:

my_structs.assign(10, a_struct(1));

Answer 2

You can't do it directly on any particular parameterized constructor. However you can do,

a_struct *my_struct[10] = {}; // create an array of pointers

for (int i = 0; i < 10; i++)
    my_struct[i] = new a_struct(i); // allocate using non-default constructor

When you're going to de-allocate the memory,

for (int i = 0; i < 10; i++)
    delete my_struct[i]  // de-allocate memory

I suggest using a std::vector container instead of going through this process.

Answer 3

You could use an array of pointers to pointers. Then you can create the array that will hold pointers to a_struct(), so you can decide later which constructor to use:

class a_class {
    a_struct ** my_structs;

    a_class() { my_structs = new a_struct* [10]}
    void foo () {
       my_structs[0] = new a_struct(1);
       my_structs[5] = new a_struct("some string and float constructor", 3.14);
    }
}; 

Answer 4

You could allocate a raw chunk of memory and use placement new to initialize each struct:

int number_of_structs = 10;
my_structs = (a_struct*)new unsigned char[sizeof(a_struct) * number_of_structs];
     // allocate a raw chunk of memory 
a_struct* p = m_structs;
for (int i=0; i<number_of_structs; i++)
{
    new (p) a_struct(i);
    p++;
}

See also: What uses are there for "placement new"?