What is the difference between int* ptr and int *ptr in C? [duplicate]

Answer 1

Like the others said. There is no difference. If you want to understand more complex C type declaration you could find this link userful. Reading C declarations.

Answer 2

It's called whitespace operator overloading, see here: http://www2.research.att.com/~bs/whitespace98.pdf

Answer 3

int *p;

*p 

is no meaning for compiler, (int*) is a type named pointer.

Answer 4

Spaces in C are mostly insignificant. There are occasional cases where spaces are important, but these are few and far between. The two examples you posted are equivalent.

Answer 5

To the compiler, there is no difference between the two declarations.

To the human reader, the former may imply that the "int*" type applies to all declarations in the same statement. However, the * binds only to the following identifier.

For example, both of the following statements declare only one pointer.

int* ptr, foo, bar;
int *ptr, foo, bar;

This statement declares multiple pointers, which prevents using the "int*" spacing.

int *ptr1, *ptr2, *ptr3;