Transform XML with XSLT in PHP

Question

I\'m trying to combine two xml-files and with a XSLT-file transform them into a XHTML-page. I have not done this before and can´t figure out how to do it. This is what I hav

Answer 1

This might be an answer to part of your question.

With regard to using two XML files, you have a couple of options. You could combine the two XML files into one larger one, then apply a transform to that. Alternatively, you could use the XSLT document() function to load one of the XML files from within an XSLT.

1. Make one large XML document

<?php

// XML
$x1 = file_get_contents("file1.xml");
$x2 = file_get_contents("file2.xml");
$xml_doc = new DOMDocument();
$xml_doc->loadXML("<root><x1>$x1</x1><x2>$x2</x2></root>");

// XSL
$xsl_doc = new DOMDocument();
$xsl_doc->load("file.xsl");

// Proc
$proc = new XSLTProcessor();
$proc->importStylesheet($xsl_doc);
$newdom = $proc->transformToDoc($xml_doc);

print $newdom->saveXML();

?>

2. Use the XSTL document() function

<?php

// XML
$xml_doc = new DOMDocument();
$xml_doc->load("file1.xml");


// XSL
$xsl_doc = new DOMDocument();
$xsl_doc->load("file.xsl");

// Proc
$proc = new XSLTProcessor();
$proc->importStylesheet($xsl_doc);
$newdom = $proc->transformToDoc($xml_doc);

print $newdom->saveXML();

?>


<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0"
    xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

  <xsl:variable name="file2" select="document('file2.xml')/*"/>

  <xsl:template match="/">
    <xsl:copy-of select="$file2"/>
  </xsl:template>

</xsl:transform>

I tend to use the first technique more than the second. I don't like hardcoding filenames into XSLT templates. When I do use the second method, I would usually pass in the filename as an external parameter to avoid having it hardcoded in the XSLT.