I have a byte array which i want to copy/clone to avoid calling code from modifying my internal representation.
How do I clone a java byte array?
In order to avoid a possible Null Pointer Exception I use the following syntax:
byte[] copy = (arr == null) ? null : arr.clone();
It's easy, and it's a great idea to do it.
byte[] copy = arr.clone();
Note that the return type of the clone()
method of arrays is the type of the array, so no cast is required.
System.arraycopy(src, 0, dst, 0, src.length);
JLS 6.4.5 The Members of an Array Type
The members of an array type are all of the following:
- The
public final field length
, which contains the number of components of the array (length may be positive or zero).- The
public
methodclone
, which overrides the method of the same name in classObject
and throws no checked exceptions. The return type of the clone method of an array typeT[]
isT[]
.- All the members inherited from class
Object
; the only method ofObject
that is not inherited is itsclone
method.
Thus:
byte[] original = ...;
byte[] copy = original.clone();
Note that for array of reference types, clone()
is essentially a shallow copy.
Also, Java doesn't have multidimensional arrays; it has array of arrays. Thus, a byte[][]
is an Object[]
, and is also subject to shallow copy.
Note that clone()
returns a new array object. If you simply want to copy the values from one array to an already existing array, you can use e.g. System.arraycopy.
There's also java.util.Arrays.copyOf that allows you to create a copy with a different length (either truncating or padding).