Retain all entries except for one key python

Question

I have a python dictionary. Just to give out context, I am trying to write my own simple cross validation unit.

So basically what I want is to get all the values exc

Answer 1

If your goal is to return a new dictionary, with all key/values except one or a few, use the following:

exclude_keys = ['exclude', 'exclude2']
new_d = {k: d[k] for k in set(list(d.keys())) - set(exclude_keys)}

where 'exclude' can be replaced by (a list of) key(s) which should be excluded.

Answer 2

Also, as a list comprehension using sets:

d = dict(zip(range(9),"abcdefghi"))
blacklisted = [2,5]
outputs = [d[k] for k in set(d.keys())-set(blacklisted)]

Answer 3

Just for fun with sets

keys = set(dict.keys())
excludes = set([...])

for key in keys.difference(excludes):
    print dict[key]

Answer 4

keys = ['a', 'b']
a_dict = {'a':1, 'b':2, 'c':3, 'd':4}
[a_dict.pop(key) for key in keys]

After popping out the keys to be discarded, a_dict will retain the ones you're after.

Answer 5

Given a dictionary say

d = {
     2: 2, 5: 16, 6: 5,
     7: 6, 11: 17, 12: 9,
     15: 18, 16: 1, 18: 16,
     19: 17, 20: 10
     }

then the simple comprehension example would attain what you possibly desire

[v for k,v in d.iteritems() if k not in (2,5)]

This example lists all values not with keys {2,5}

for example the O/P of the above comprehension is

[5, 6, 1, 17, 9, 18, 1, 16, 17, 10]

Answer 6

for key, value in your_dict.items():
    if key not in your_blacklisted_set:
        print value

the beauty is that this pseudocode example is valid python code.

it can also be expressed as a list comprehension:

resultset = [value for key, value in your_dict.items() if key not in your_blacklisted_set]