Standard conformant way of converting std::time_t to System::DateTime?

Question

I have already found several answers related to converting a std::time_t value to System::DateTime and back. However, almost all answers seem to ne

Answer 1

It just isn't very productive to insist on a "standard conformant" way to make this conversion. The only place where an std::time_t and a System::DateTime are ever going to meet is covered by the Ecma-372 standard. Of which there is right now, and surely will ever be, only one implementation. The Mono project could be assumed to be the most likely source of another one, but right now they appear entirely uninterested in providing a mixed-mode implementation, the only reason you'd ever consider using C++/CLI.

std::time_t is steadily marching towards the Y2K38 disaster. With Microsoft pre-emptively having done something about it, and really having to do so because they went for LLP64, but everybody else counting on their LP64 data model keeping them out of trouble. In other words, no remaining 32-bit processors still running in 2038. This could well be a self-fulfilling prophesy.

Regardless, the conversion is going to have to work with elapsed seconds since 1/1/1970. And that can be a 32-bit or a 64-bit integral value, depending on implementation. The only warranty I can give is that this code is at least good until 2038:

#include <ctime>

using namespace System;

public ref class Conversions {
public:
    static DateTime time_t2DateTime(std::time_t date) {
        double sec = static_cast<double>(date);
        return DateTime(1970, 1, 1, 0, 0, 0, DateTimeKind::Utc).AddSeconds(sec);
    }
    static std::time_t DateTime2time_t(DateTime date) {
        TimeSpan diff = date.ToUniversalTime() - DateTime(1970, 1, 1);
        return static_cast<std::time_t>(diff.TotalSeconds);
    }
};

Answer 2

Here's the solution my team arrived at:

DateTime represents the number of mixed-fractional days since midnight December 30, 1899, expressed as a double. I believe that this epoch date was used to account for the fact that 1900 was not a leap year, and it allows for an extra two days (Why two and not one? - It is not clear to me why Dec 31, 1899 was not chosen as their epoch.)

So a DateTime of 2.50 would be equivalent to January 1, 1900 12:00:00 , (i.e. the fraction represents 1/2 the day - 12PM).

We calculated that Jan 1, 1970 - the Unix Epoch - is 25569 days after the DateTime Epoch.

So the equivalent formula would be:

#include <time.h>
System::DateTime toDateTime(time_t &t)
{
    return 25569.0 + t / 86400.0; // ensure you use floating point math or you will truncate the fractional portion
}