Listview win8 xaml how to create columns?

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日久生厌
日久生厌 2020-12-10 07:58

Hi I am trying to create 3 columns in a ListView.

I read this but I want to set the data in each column programtically in C#:

how to display data in rows and

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  • 2020-12-10 08:44

    Improved XAML of Seb Boulet's answer if you don't want to hard code the Width of the Item/Grid (responsive design):

    <ListView Name="ListViewSongs">
        <ListView.ItemContainerStyle>
            <Style TargetType="ListViewItem">
                <Setter Property="HorizontalContentAlignment" Value="Stretch"></Setter>
            </Style>
        </ListView.ItemContainerStyle>
        <ListView.ItemTemplate>
            <DataTemplate>
                <Grid>
                    <Grid.ColumnDefinitions>
                        <ColumnDefinition Width="120" />
                        <ColumnDefinition Width="*" />
                        <ColumnDefinition Width="150" />
                    </Grid.ColumnDefinitions>
                    <TextBlock Grid.Column="0" Text="{Binding Artist}" />
                    <TextBlock Grid.Column="1" Text="{Binding ArtistName}" />
                    <TextBlock Grid.Column="2" Text="{Binding SongName}" />
                </Grid>
            </DataTemplate>
        </ListView.ItemTemplate>
    </ListView>
    

    Related topic: How to get a ListBox ItemTemplate to stretch horizontally the full width of the ListBox?

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  • 2020-12-10 08:59

    Assuming you have something like this to store your data:

    public class SongDetails
    {
        public string ArtistName {get; set;}
        public string SongName {get; set;}
        public string Artist {get; set;}
    }
    

    And a ListView with a DataTemplate defined (as in the link you provided), just give your ListView a name:

    <ListView Name="ListViewSongs">
        <ListView.ItemTemplate>
            <DataTemplate>
                <Grid Width="500" VerticalAlignment="Center">
    
                    <Grid.ColumnDefinitions>
                        <ColumnDefinition Width="120" />
                        <ColumnDefinition Width="*" />
                        <ColumnDefinition Width="150" />
                    </Grid.ColumnDefinitions>
    
                    <TextBlock Grid.Column="0" Text="{Binding Artist}" />
                    <TextBlock Grid.Column="1" Text="{Binding ArtistName}" />
                    <TextBlock Grid.Column="2" Text="{Binding SongName}" />
                </Grid>
            </DataTemplate>
        </ListView.ItemTemplate>
    </ListView>
    

    Then, from the code-behind, it's just a case of:

    var songDetails = new[]
        {
            new SongDetails {Artist = "a1", ArtistName = "a2", SongName = "a3"},
            new SongDetails {Artist = "b1", ArtistName = "b2", SongName = "b3"}
        };
    
    ListViewSongs.ItemsSource = songDetails;
    
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