How Sort Array Date JavaScript dd/mm/yyyy?

Question

How would I sort an array of dates in chronological order? For example I have:

var dates = [
    \'03/03/2014\',
             


        

Answer 1

Please do this the easy way.
Works for dates formatted as 'dd/mm/yy' or 'dd/mm/yyyy'.

var dates = [
    '03/03/2014',
    '01/03/2014',
    '02/03/2014',
    '04/03/2014'
];

dates.sort( function(c,d){
    var rx = /(\d+)\/(\d+)\/(\d+)/;
    var a = Number(c.replace(rx, '$3$1$20000'));
    var b = Number(d.replace(rx, '$3$1$20000'));
    return a > b ? -1 : a == b ? 0 : 1; // for newer on top
    //return a < b ? -1 : a == b ? 0 : 1; // for older on top
  });

Answer 2

Digigizmo answer works!

in case: dd/mm/yyyy hh:mm:ss you can use:

list.sort(function (a, b) {
    var aa = a.substring(0, 10).split('/').reverse().join() + replaceAll(':', '', a.substring(11, 20)),
    bb = b.substring(0, 10).split('/').reverse().join() + replaceAll(':', '', b.substring(11, 20));
    return aa < bb ? -1 : (aa > bb ? 1 : 0);
});

and replaceAll function:

function replaceAll(find, replace, str) {
  return str.replace(new RegExp(find, 'g'), replace);
}

Answer 3

Try this (feel free to ask for details) :

dates.sort(function (a, b) {
    // '01/03/2014'.split('/')
    // gives ["01", "03", "2014"]
    a = a.split('/');
    b = b.split('/');
    return a[2] - b[2] || a[1] - b[1] || a[0] - b[0];
});

Translation of the last line :

return          return
a[2] - b[2]     years comparison if year A - year B is not 0
||              or
a[1] - b[1]     months comparison if month A - month B is not 0
||              or
a[0] - b[0];    days comparison

https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/sort.

Answer 4

Assuming your date format is consistently DD/MM/YYYY:

dates.sort(function(a, b){
    var aa = a.split('/').reverse().join(),
        bb = b.split('/').reverse().join();
    return aa < bb ? -1 : (aa > bb ? 1 : 0);
});

... otherwise you will have to compare Date objects if you require more flexibility.

Answer 5

Just improving @leaf answer as split works on strings so you might get error if the type of 'a' and 'b' is object.

dates.sort(function (a, b) {
        a = a.toString().split('/');
        b = b.toString().split('/');
        return a[2] - b[2] || a[1] - b[1] || a[0] - b[0];
    });