Accept permission request in chrome using selenium

Question

I have a HTML/Javascript file with google\'s web speech api and I\'m doing testing using selenium, however everytime I enter the site the browser requests permission to use

Answer 1

@ExperimentsWithCode

Thank you for your answer again, I have spent almost the whole day today trying to figure out how to do this and I've also tried your suggestion where you add that flag --disable-user-media-security to chrome, unfortunately it didn't work for me.

However I thought of a really simple solution:

To automatically click on Allow all I have to do is press TAB key three times and then press enter. And so I have written the program to do that automatically and it WORKS !!!

The first TAB pressed when my html page opens directs me to my input box, the second to the address bar and the third on the ALLOW button, then the Enter button is pressed.

The python program uses selenium as well as PyWin32 bindings.

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Thank you for taking your time and trying to help me it is much appreciated.

Answer 2

Building on the answer from @Shady Programmer.

I tried to send Tab keys with selenium in order to focus on the popup, but as reported by others it didn't work in Linux. Therefore, instead of using selenium keys, I use xdotool command from python :

def send_key(winid, key):
    xdotool_args = ['xdotool', 'windowactivate', '--sync', winid, 'key', key]
    subprocess.check_output(xdotool_args)

which for Firefox, gives the following approximate sequence :

# Focusing on permissions popup icon
for i in range(6):
    time.sleep(0.1)
    send_key(win_info['winid'], 'Tab')

# Enter permissions popup
time.sleep(0.1)
send_key(win_info['winid'], 'space')

# Focus on "accept" button
for i in range(3):
    time.sleep(0.1)
    send_key(win_info['winid'], 'Tab')

# Press "accept"            
send_key(win_info['winid'], 'a')