java.lang.IllegalArgumentException: Invalid URL or resource not found

Question

I tested this code:

public static void main(String[] args)
    {
        Application.launch(args);
    }

    @Override
    public void start(Stage primarySt         


        

Answer 1

Do

javafx.scene.image.Image image = new javafx.scene.image.Image(getClass().getResource("za.jpg").toExternalForm());
ImageView iv = new ImageView(image);

Or simply

ImageView iv = new ImageView(getClass().getResource("za.jpg").toExternalForm());

Answer 2

Image image = new Image("za.png");

The constructor of this needs to point to a URI, so if you're pointing to something on the file system it'd be:

Image image = new Image("file:za.png");

Alternatively, you could do:

Image image = new Image(new File("za.png").toURI().toString());

...which is arguably neater. If the image is bundled in your jar rather than on the filesystem, you can obtain the URI like so:

Image image = new Image(getClass().getResource("za.jpg").toURI().toString());

Most methods / constructors in JavaFX that take a string as a parameter in this way (i.e. specifying a resource) do so via string URI's rather than just a plain file path or URL.