Check a variable against Union type at runtime in Python 3.6

Question

UPDATE (September 2020): Python 3.9 includes the typing.get_type_hints function for this use case, see https://docs.python.org/3.9/library/typ

Answer 1

The existing accepted answer by MSeifert (https://stackoverflow.com/a/45959000/7433423) does not distinguish Unions from other generic types, and it is difficult to determine at runtime whether a type annotation is a Union or some other generic type like Mapping due to the behavior of isinstance() and issubclass() on parameterized Union types.

It appears that generic types will have an undocumented __origin__ attribute which will contain a reference to the original generic type used to create it. Once you have confirmed that the type annotation is a parameterized Union, you can then use the also undocumented __args__ attribute to get the type parameters.

>>> from typing import Union
>>> type_anno = Union[int, str]
>>> type_anno.__origin__ is Union
True
>>> isinstance(3, type_anno.__args__)
True
>>> isinstance('a', type_anno.__args__)
True

Answer 2

You could use the __args__ attribute of Union which holds a tuple of the "possible contents:

>>> from typing import Union

>>> x = Union[int, str]
>>> x.__args__
(int, str)
>>> isinstance(3, x.__args__)
True
>>> isinstance('a', x.__args__)
True

The __args__ argument is not documented so it could be considered "messing with implementation details" but it seems like a better way than parsing the repr.

Answer 3

In Python 3.8 and later, the approach suggested by MSeifert and Richard Xia can be improved by not using the undocumented attributes __origin__ and __args__. This functionality is provided by the new functions typing.get_args(tp) and typing.get_origin(tp):

>> from typing import Union, get_origin, get_args
>> x = Union[int, str]
>> get_origin(x), get_args(x)
(typing.Union, (<class 'int'>, <class 'str'>))
>> get_origin(x) is Union
True
>> isinstance(3, get_args(x))
True
>> isinstance('a', get_args(x))
True
>> isinstance([], get_args(x))
False

P.S.: I know that the question is about Python 3.6 (probably because this was the newest version at the time), but I arrived here when I searched for a solution as a Python 3.8 user. I guess that others might be in the same situation, so I thought that adding a new answer here makes sense.

Answer 4

You can use the typeguard module which can be installed with pip. It provides you with a function check_argument_types or a function decorator @typechecked. which should do your runtime type checking for you: https://github.com/agronholm/typeguard

from typing import Union
from typeguard import check_argument_types, typechecked

def check_and_do_stuff(a: Union[str, int]) -> None:
    check_argument_types() 
    # do stuff ...

@typechecked
def check_decorator(a: Union[str, int]) -> None:
    # do stuff ...

check_and_do_stuff("hello")
check_and_do_stuff(42)
check_and_do_stuff(3.14)  # raises TypeError

If you want to check a type of a single variable for a different reason, you can use typeguard's check_type function directly:

from typing import Union
from typeguard import check_type

MyType = Union[str, int]

check_type("arg", "string", MyType, None)  # OK
check_type("arg", 42, MyType, None)  # OK
check_type("arg", 3.5, MyType, None)  # raises TypeError

The "arg" and None arguments are unused in this example. Note that the check_type function is not documented as a public function of this module so its API may be subject to change.