Validate phone number ios

Question

I need to validate an international phone number.

I know its difficult to validate an international phone number, so I\'m going to keep it simple:

+

Answer 1

NSString *phoneRegex = @"^((\\+)|(00))[0-9]{6,14}$";

This way is bit better. Your code will work as well if you escape the "\".

Answer 2

well it depends on how strict you want to be it doesn't seem like this regex is especially strict. this regex says:

start at beginning of line match one + (or maybe 1 or 0) which seems ambiguous (but may not be depending on implementation) because the capture parentheses:() breaks up the relationship of the + and the ? possibly misplaced : match any digit 0-9 1 or 0 times 6-14 times then one digit 0-9 then end of line. also you note that any backslash will have to be doubled... @"\b" for a word boundary. you may want to try something like...

@"\\b[\\d]{3}\\-[\\d]{3}\\-[\\d]{4}\\b"
would I think match your example, but it wouldn't match
(555) 555 - 5555 or
555.555.5555 or
+44 1865  55555

Answer 3

Easy way to validate phone number and password limit , just follow the below process.

if ((self.mobileTxtFld.text.length < 10 )) {
    [_mobileTxtFld becomeFirstResponder];
}
else if ((self.passwordTxtFld.text.length < kPasswordCharacterMinLimit) || (self.passwordTxtFld.text.length > kPasswordCharacterMaxLimit)) {
    // show alert
}

after that you can implement textfiled delegate method "shouldChangeCharactersInRange" in that just write this code

if (textField == _mobileTxtFld) {
    if([string rangeOfCharacterFromSet:ALLOWED_NUMBERS].location == NSNotFound){
        NSUInteger newLength = [textField.text length] + [string length] - range.length;
        if(newLength > kMobileNumberLimit - 1){
            if(textField.text.length != kMobileNumberLimit){
                textField.text  = [NSString stringWithFormat:@"%@%@",textField.text,string];
            }
            [textField resignFirstResponder];
            return NO;
        }
        else{
            return YES;
        }
    }
    else{
        return NO;
    }
}

return YES;

here ALLOWED_NUMBERS and kMobileNumberLimit are

#define kMobileNumberLimit 10
#define ALLOWED_NUMBERS [[NSCharacterSet decimalDigitCharacterSet] invertedSet]
#define minLimit 6
#define maxLimit 17

Answer 4

NSString *phoneRegex = @"^((\\+)|(00))[0-9]{6,14}|[0-9]{6,14}$";

This is tested RegularExpression This will accept with country code OR without country code

Answer 5

The only good way to validate phone numbers is to use Google's amazing LibPhoneNumber. There's an iOS port, or you can run the JavaScript implementation in a hidden UIWebView.

(I've done the latter years ago when their was no iOS port yet. Works like a charm and is very fast even on old iPhones.)

Answer 6

-(int)findLength:(NSString*)phoneNumber
{
    phoneNumber = [phoneNumber stringByReplacingOccurrencesOfString:@"(" withString:@""];
    phoneNumber = [phoneNumber stringByReplacingOccurrencesOfString:@")" withString:@""];
    phoneNumber = [phoneNumber stringByReplacingOccurrencesOfString:@" " withString:@""];
    phoneNumber = [phoneNumber stringByReplacingOccurrencesOfString:@"-" withString:@""];
    phoneNumber = [phoneNumber stringByReplacingOccurrencesOfString:@"+" withString:@""];

int length = [phoneNumber length];

return length;

}