Declaring multiple TypeScript variables with the same type

Question

I\'m coding a large TypeScript class and I\'ve set noImplicitAny to true. Is there any way to declare multiple variables of the same type on the same line?

I\'d lik

Answer 1

There is no real way to achieve what you want. If your only goal is to compress everything onto one line, you can do the following:

public AcccountNumber: number;public branchCode:number;

…but I wouldn't recommend it.

Answer 2

let [string1, string2]: string[] = [];

breaking it down:

• on the left the whole [string1, string2] is declared as string[], implying string1, string2 is of type string
• to do a destructure you need it to be assigned to something, here empty array []
• on right hand the empty array is [undefined, undefined, undefined, ...] when destructuring string1 and string2 gets assigned to undefined
• finally string1, string2 are of type string with value undefined

Answer 3

let notes: string = '', signatureTypeName = '';

Answer 4

If you can accept an orphan variable. Array destructuring can do this.

var numberArray:number[]; //orphan variable
var [n1,n2,n3,n4] = numberArray;
n1=123; //n1 is number
n1="123"; //typescript compile error

Update: Here is the Javascript code generated, when targeting ECMAScript 6.

var numberArray; //orphan variable
var [n1, n2, n3, n4] = numberArray;
n1 = 123; //n1 is number

JS Code generated when targeting ECMAScript 5, like Louis said below, it's not pretty.

var numberArray; //orphan variable
var n1 = numberArray[0], n2 = numberArray[1], n3 = numberArray[2], n4 = numberArray[3];
n1 = 123; //n1 is number

Answer 5

e.g. let isFormSaved, isFormSubmitted, loading: boolean = false; this syntax only works in function block, but not outside of it in typescript export class file. Not sure why is that.

For Example:

export class SyntaxTest {

public method1() {
    e.g. let isFormSaved, isFormSubmitted, loading: boolean = false;
}

}