Unzip zip files in folders and subfolders with python

Question

I try to unzip 150 zip files. All the zip files as different names, and they all spread in one big folder that divided to a lot of sub folders and sub sub folders.i want to

Answer 1

UPDATE:

Finally, this code worked for me:

import zipfile,fnmatch,os

rootPath = r"C:\Project"
pattern = '*.zip'
for root, dirs, files in os.walk(rootPath):
    for filename in fnmatch.filter(files, pattern):
        print(os.path.join(root, filename))
        zipfile.ZipFile(os.path.join(root, filename)).extractall(os.path.join(root, os.path.splitext(filename)[0]))

Answer 2

You could use Path.rglob() to enumerate zip-files recursively and shutil.unpack_archive() to unpack zip files:

#!/usr/bin/env python3
import logging
from pathlib import Path
from shutil import unpack_archive

zip_files = Path(r"C:\Project\layers").rglob("*.zip")
while True:
    try:
        path = next(zip_files)
    except StopIteration:
        break # no more files
    except PermissionError:
        logging.exception("permission error")
    else:
         extract_dir = path.with_name(path.stem)
         unpack_archive(str(path), str(extract_dir), 'zip')

It "extract[s] each archive to separate folder with the same name as the original zip file name and also in the same place as the original zip file" e.g., it extracts 'layers/dir/file.zip' archive into 'layers/dir/file' directory.

Answer 3

To unzip all the files into a temporary folder (Ubuntu)

import tempfile
import zipfile

tmpdirname = tempfile.mkdtemp()

zf = zipfile.ZipFile('/path/to/zipfile.zip')

for fn in zf.namelist():
    temp_file = tmpdirname+"/"+fn
    #print(temp_file)

    f = open(temp_file, 'w')
    f.write(zf.read(fn).decode('utf-8'))
    f.close()